What is the answer to 2^2x+3+2^x+3=1+2^x ?

The answer to 2^2x+3+2^x+3=1+2^x is x=-5/4

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2^2x+3+2^x+3=1+2^x

2^{2} x + 3 + 2^{x} + 3 = 1 + 2^{x}

x = - \frac{5}{4}

Decimal Notation

x = - 1.25

Solution steps

2^{2} x + 3 + 2^{x} + 3 = 1 + 2^{x}

Subtract

2^{x}

from both sides

2^{2} x + 3 + 2^{x} + 3 - 2^{x} = 1 + 2^{x} - 2^{x}

Simplify

4 x + 6 = 1

Solve

4 x + 6 = 1 : x = - \frac{5}{4}

x = - \frac{5}{4}

(\frac{1}{32})^{x + 2} = 8^{x + 1}

2^{x} - 1 + 2^{x} + 2^{x} + 1 = 7

3^{2 x - 5} + 9^{x - 2} = 4

(\frac{1}{16})^{x} = (\frac{1}{8})^{6}

3^{x + 1} = 81

What is the answer to 2^2x+3+2^x+3=1+2^x ?
The answer to 2^2x+3+2^x+3=1+2^x is x=-5/4
Solve for x: 2^2x+3+2^x+3=1+2^x
The solution is x=-5/4