What is the answer to 14800=7400*(1+(3/100))^x ?

The answer to 14800=7400*(1+(3/100))^x is x=(ln(2))/(ln(103/100))

Solve for x: 14800=7400*(1+(3/100))^x

The solution is x=(ln(2))/(ln(103/100))

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14800 = 7400 \cdot (1 + (\frac{3}{100}))^{x}

x = \frac{ln ( 2 )}{ln ( \frac{103}{100} )}

Decimal Notation

x = 23.44977 \dots

Solution steps

14800 = 7400 (1 + (\frac{3}{100}))^{x}

Switch sides

7400 (1 + \frac{3}{100})^{x} = 14800

Divide both sides by

7400

(1 + \frac{3}{100})^{x} = 2

Apply exponent rules

x ln (1 + \frac{3}{100}) = ln (2)

Solve

x ln (1 + \frac{3}{100}) = ln (2) : x = \frac{ln ( 2 )}{ln ( \frac{103}{100} )}

x = \frac{ln ( 2 )}{ln ( \frac{103}{100} )}

(m - 2)^{m - 2} = 14 4^{6}

2^{x} - 2 + 2^{3} - x = 3

5^{b} = 2 5^{b} - 1

2 e^{y} + 15 e^{- y} = 11

2.16 = (1 + 0.12)^{n - 1}

What is the answer to 14800=7400*(1+(3/100))^x ?
The answer to 14800=7400*(1+(3/100))^x is x=(ln(2))/(ln(103/100))
Solve for x: 14800=7400*(1+(3/100))^x
The solution is x=(ln(2))/(ln(103/100))