What is -4<= (2k-1)/3 <= 2 ?

The solution to -4<= (2k-1)/3 <= 2 is -11/2 <= k<= 7/2

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-4<= (2k-1)/3 <= 2

- 4 \leq \frac{2 k - 1}{3} \leq 2

- \frac{11}{2} \leq k \leq \frac{7}{2}

Solution steps

- 4 \leq \frac{2 k - 1}{3} \leq 2

a \leq u \leq b

then

a \leq u and u \leq b

- 4 \leq \frac{2 k - 1}{3} and \frac{2 k - 1}{3} \leq 2

- 4 \leq \frac{2 k - 1}{3} : k \geq - \frac{11}{2}

\frac{2 k - 1}{3} \leq 2 : k \leq \frac{7}{2}

Combine the intervals

k \geq - \frac{11}{2} and k \leq \frac{7}{2}

Merge Overlapping Intervals

- \frac{11}{2} \leq k \leq \frac{7}{2}

x^{2} - x - 6 = 5

5 b^{3} - 20 b

36 m^{2} - 84 m + 49 = 0

\frac{2 ^{5}}{2 ^{7}}

1.5 \cdot 3

What is -4<= (2k-1)/3 <= 2 ?
The solution to -4<= (2k-1)/3 <= 2 is -11/2 <= k<= 7/2