What is the answer to 7^{x-3}*2^{2x-3}=224 ?

The answer to 7^{x-3}*2^{2x-3}=224 is x=(ln(1792)+3ln(7))/(ln(28))

Solve for x: 7^{x-3}*2^{2x-3}=224

The solution is x=(ln(1792)+3ln(7))/(ln(28))

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7^{x - 3} \cdot 2^{2 x - 3} = 224

x = \frac{ln ( 1792 ) + 3 ln ( 7 )}{ln ( 28 )}

Decimal Notation

x = 4

Solution steps

7^{x - 3} \cdot 2^{2 x - 3} = 224

Apply exponent rules

(lo g_{2} (7) (x - 3) + 2 x - 3) ln (2) = ln (224)

Solve

(lo g_{2} (7) (x - 3) + 2 x - 3) ln (2) = ln (224) : x = \frac{ln ( 1792 ) + 3 ln ( 7 )}{ln ( 28 )}

x = \frac{ln ( 1792 ) + 3 ln ( 7 )}{ln ( 28 )}

2^{3} = 3^{x}

(\frac{1}{6})^{x} - 13 = 64

3^{x} = 54

3^{x} = 50

2^{x + 2} + 2^{x} = 2^{2}

What is the answer to 7^{x-3}*2^{2x-3}=224 ?
The answer to 7^{x-3}*2^{2x-3}=224 is x=(ln(1792)+3ln(7))/(ln(28))
Solve for x: 7^{x-3}*2^{2x-3}=224
The solution is x=(ln(1792)+3ln(7))/(ln(28))