What is the answer to 25^{x-1}+100=((5^{2x}))/5 ?

The answer to 25^{x-1}+100=((5^{2x}))/5 is x=2

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25^{x-1}+100=((5^{2x}))/5

2 5^{x - 1} + 100 = \frac{( 5 ^{2 x} )}{5}

x = 2

Solution steps

2 5^{x - 1} + 100 = \frac{( 5 ^{2 x} )}{5}

Apply exponent rules

2 x = 4

Solve

2 x = 4 : x = 2

x = 2

a, a^{a} + 5 = b^{b} + a^{a} - 2^{2}

3^{x - 1} - 10 = 17

(2^{x})^{2} = (1 2^{x})^{2}

2^{x + 4} - 2^{x + 3} = 1

p, \frac{a ^{8}}{a ^{p}} = a^{2}

What is the answer to 25^{x-1}+100=((5^{2x}))/5 ?
The answer to 25^{x-1}+100=((5^{2x}))/5 is x=2
Solve for x: 25^{x-1}+100=((5^{2x}))/5
The solution is x=2