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Popular >

1/((1+x^{a-b))}+1/((1+x^{b-a))}=1

Solution

\frac{1}{( 1 + x ^{a - b} )} + \frac{1}{( 1 + x ^{b - a} )} = 1

Solution

True for all x; (x^{a - b} + 1) (x^{b - a} + 1) \neq = 0

Solution steps

\frac{1}{( 1 + x ^{a - b} )} + \frac{1}{( 1 + x ^{b - a} )} = 1

Multiply by LCM

x^{b - a} + x^{a - b} + 2 = (x^{a - b} + 1) (x^{b - a} + 1); (x^{a - b} + 1) (x^{b - a} + 1) \neq = 0

Solve

x^{b - a} + x^{a - b} + 2 = (x^{a - b} + 1) (x^{b - a} + 1) :

True for all

x

True for all x; (x^{a - b} + 1) (x^{b - a} + 1) \neq = 0

Popular Examples

(x^2+1)/((x^2)-5(x+1/x)+8)=0

\frac{x ^{2} + 1}{( x ^{2} ) - 5 ( x + \frac{1}{x} ) + 8} = 0

1=(1.5h)/(800+h)

1 = \frac{1.5 h}{800 + h}

(x^2+1)/(x^2-5(x+1/x)+8)=0

\frac{x ^{2} + 1}{x ^{2} - 5 ( x + \frac{1}{x} ) + 8} = 0

(x+1)/x = 21/20

\frac{x + 1}{x} = \frac{21}{20}

xx^3+(x/1)/(5/x)= 9/10

x x^{3} + \frac{\frac{x}{1}}{\frac{5}{x}} = \frac{9}{10}

Frequently Asked Questions (FAQ)

What is the answer to 1/((1+x^{a-b))}+1/((1+x^{b-a))}=1 ?
The answer to 1/((1+x^{a-b))}+1/((1+x^{b-a))}=1 is True for all x;\quad (x^{a-b}+1)(x^{b-a}+1)\ne 0