What is the answer to (x^2+1)/(x^2-5(x+1/x)+8)=0 ?

The answer to (x^2+1)/(x^2-5(x+1/x)+8)=0 is x=i,x=-i

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(x^2+1)/(x^2-5(x+1/x)+8)=0

\frac{x ^{2} + 1}{x ^{2} - 5 ( x + \frac{1}{x} ) + 8} = 0

x = i, x = - i

Solution steps

\frac{x ^{2} + 1}{x ^{2} - 5 ( x + \frac{1}{x} ) + 8} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} + 1 = 0

Solve

x^{2} + 1 = 0 : x = i, x = - i

x = i, x = - i

\frac{x + 1}{x} = \frac{21}{20}

x x^{3} + \frac{\frac{x}{1}}{\frac{5}{x}} = \frac{9}{10}

g = \frac{10 m}{s ^{2}}

\frac{31}{2 - 4 ( 2 x - 3 )} = \frac{1}{3 ( \frac{3}{4} - 6 x )}

\frac{1}{x} + \frac{1}{5} = \frac{4}{5}

What is the answer to (x^2+1)/(x^2-5(x+1/x)+8)=0 ?
The answer to (x^2+1)/(x^2-5(x+1/x)+8)=0 is x=i,x=-i
Solve for x: (x^2+1)/(x^2-5(x+1/x)+8)=0
The solution is x=i,x=-i