What is the answer to x^{-3}= 27/64 ?

The answer to x^{-3}= 27/64 is x= 4/3 ,x=-2/3+2/(sqrt(3))i,x=-2/3-2/(sqrt(3))i

Solve for x: x^{-3}= 27/64

The solution is x= 4/3 ,x=-2/3+2/(sqrt(3))i,x=-2/3-2/(sqrt(3))i

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x^{- 3} = \frac{27}{64}

x = \frac{4}{3}, x = - \frac{2}{3} + \frac{2}{3} i, x = - \frac{2}{3} - \frac{2}{3} i

Solution steps

x^{- 3} = \frac{27}{64}

Refine

\frac{1}{x ^{3}} = \frac{27}{64}

Cross multiply

64 = x^{3} \cdot 27

Solve

64 = x^{3} \cdot 27 : x = \frac{4}{3}, x = - \frac{2}{3} + \frac{2}{3} i, x = - \frac{2}{3} - \frac{2}{3} i

x = \frac{4}{3}, x = - \frac{2}{3} + \frac{2}{3} i, x = - \frac{2}{3} - \frac{2}{3} i

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{4}{3}, x = - \frac{2}{3} + \frac{2}{3} i, x = - \frac{2}{3} - \frac{2}{3} i

\frac{x ^{2} - ( 3 a )}{2 \cdot x - a ^{2}} = 0

\frac{2}{( x + 2 )} - \frac{1}{( x + 1 )} = \frac{4}{( x + 4 )} - \frac{3}{( x + 3 )}

\frac{9 - 3 y}{1 - 9 y} = \frac{8}{5}

\frac{1}{x ^{2}} + 3 x + 2 - \frac{3}{x ^{2}} - x - 2 = - \frac{1}{x ^{2}} - 4

x^{2} + \frac{1}{( x ^{2} )} + 5 x - \frac{5}{x} + 4 = 0

What is the answer to x^{-3}= 27/64 ?
The answer to x^{-3}= 27/64 is x= 4/3 ,x=-2/3+2/(sqrt(3))i,x=-2/3-2/(sqrt(3))i
Solve for x: x^{-3}= 27/64
The solution is x= 4/3 ,x=-2/3+2/(sqrt(3))i,x=-2/3-2/(sqrt(3))i