What is the answer to 2/((x+2))-1/((x+1))= 4/((x+4))-3/((x+3)) ?

The answer to 2/((x+2))-1/((x+1))= 4/((x+4))-3/((x+3)) is x=0,x=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2/((x+2))-1/((x+1))= 4/((x+4))-3/((x+3))

\frac{2}{( x + 2 )} - \frac{1}{( x + 1 )} = \frac{4}{( x + 4 )} - \frac{3}{( x + 3 )}

x = 0, x = - \frac{5}{2}

Decimal Notation

x = 0, x = - 2.5

Solution steps

\frac{2}{( x + 2 )} - \frac{1}{( x + 1 )} = \frac{4}{( x + 4 )} - \frac{3}{( x + 3 )}

Multiply by LCM

2 (x + 1) (x + 4) (x + 3) - (x + 2) (x + 4) (x + 3) = 4 (x + 2) (x + 1) (x + 3) - 3 (x + 2) (x + 1) (x + 4)

Solve

2 (x + 1) (x + 4) (x + 3) - (x + 2) (x + 4) (x + 3) = 4 (x + 2) (x + 1) (x + 3) - 3 (x + 2) (x + 1) (x + 4) : x = 0, x = - \frac{5}{2}

x = 0, x = - \frac{5}{2}

Verify Solutions

Find undefined (singularity) points:

x = - 2, x = - 1, x = - 4, x = - 3

Combine undefined points with solutions:

x = 0, x = - \frac{5}{2}

\frac{9 - 3 y}{1 - 9 y} = \frac{8}{5}

\frac{1}{x ^{2}} + 3 x + 2 - \frac{3}{x ^{2}} - x - 2 = - \frac{1}{x ^{2}} - 4

x^{2} + \frac{1}{( x ^{2} )} + 5 x - \frac{5}{x} + 4 = 0

m^{1} = \frac{- 1}{m ^{2}}

\frac{a}{( x - a )} + \frac{b}{( x - b )} = \frac{( 2 c )}{( x - c )}

What is the answer to 2/((x+2))-1/((x+1))= 4/((x+4))-3/((x+3)) ?
The answer to 2/((x+2))-1/((x+1))= 4/((x+4))-3/((x+3)) is x=0,x=-5/2
Solve for x: 2/((x+2))-1/((x+1))= 4/((x+4))-3/((x+3))
The solution is x=0,x=-5/2