What is the answer to m^1=(-1)/(m^2) ?

The answer to m^1=(-1)/(m^2) is m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i

Solve for m: m^1=(-1)/(m^2)

The solution is m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i

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m^{1} = \frac{- 1}{m ^{2}}

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

Solution steps

m^{1} = \frac{- 1}{m ^{2}}

Simplify

\frac{- 1}{m ^{2}} : - \frac{1}{m ^{2}}

m^{1} = - \frac{1}{m ^{2}}

Multiply both sides by

m^{2}

m^{3} = - 1

Solve

m^{3} = - 1 : m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

Verify Solutions

Find undefined (singularity) points:

m = 0

Combine undefined points with solutions:

m = - 1, m = \frac{1}{2} - \frac{3}{2} i, m = \frac{1}{2} + \frac{3}{2} i

\frac{a}{( x - a )} + \frac{b}{( x - b )} = \frac{( 2 c )}{( x - c )}

2 (\frac{2 x - 1}{x + 3}) - 3 (\frac{x + 3}{2 x - 1}) = 5

x, \frac{1}{x} + \frac{1}{y} = 1

2 (\frac{x ^{2} + 1}{( x ^{2} )}) - 3 (\frac{x - 1}{x}) - 4 = 0

\frac{( 2 ^{n} + 2 ^{n - 1} )}{( 2 ^{n + 1} - 2 ^{n} )} = \frac{3}{2}

What is the answer to m^1=(-1)/(m^2) ?
The answer to m^1=(-1)/(m^2) is m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i
Solve for m: m^1=(-1)/(m^2)
The solution is m=-1,m= 1/2-(sqrt(3))/2 i,m= 1/2+(sqrt(3))/2 i