What is the answer to 1/((a+b+x))= 1/a+1/b+1/x ?

The answer to 1/((a+b+x))= 1/a+1/b+1/x is x=-b,x=-a;\quad a+b\ne 0

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1/((a+b+x))= 1/a+1/b+1/x

\frac{1}{( a + b + x )} = \frac{1}{a} + \frac{1}{b} + \frac{1}{x}

x = - b, x = - a; a + b \neq = 0

Solution steps

\frac{1}{( a + b + x )} = \frac{1}{a} + \frac{1}{b} + \frac{1}{x}

Multiply by LCM

ab x = b x (x + a + b) + a x (x + a + b) + ab (x + a + b)

Solve

ab x = b x (x + a + b) + a x (x + a + b) + ab (x + a + b) : x = - b, x = - a; a + b \neq = 0

x = - b, x = - a; a + b \neq = 0

\frac{\frac{1}{2}}{\frac{3}{2}} = \frac{0.1}{x}

(3 x - 1.5) \cdot (\frac{- 1}{2 x + 5}) = 0

\frac{3.5}{x} = 14

\frac{3}{∣ x + 1 ∣} + \frac{∣ x + 1 ∣}{3} = 2

\frac{( ( 2 ∣ x ∣ - 3 ) ^{2} - ∣ x ∣ - 6 )}{( 4 x + 1 )} = 0

What is the answer to 1/((a+b+x))= 1/a+1/b+1/x ?
The answer to 1/((a+b+x))= 1/a+1/b+1/x is x=-b,x=-a;\quad a+b\ne 0