What is the answer to (((2|x|-3)^2-|x|-6))/((4x+1))=0 ?

The answer to (((2|x|-3)^2-|x|-6))/((4x+1))=0 is x= 1/4 ,x=-3,x=3

Solve for x: (((2|x|-3)^2-|x|-6))/((4x+1))=0

The solution is x= 1/4 ,x=-3,x=3

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\frac{( ( 2 ∣ x ∣ - 3 ) ^{2} - ∣ x ∣ - 6 )}{( 4 x + 1 )} = 0

x = \frac{1}{4}, x = - 3, x = 3

Decimal Notation

x = 0.25, x = - 3, x = 3

Solution steps

\frac{( ( 2 ∣ x ∣ - 3 ) ^{2} - ∣ x ∣ - 6 )}{( 4 x + 1 )} = 0

Simplify

\frac{( 2 ∣ x ∣ - 3 ) ^{2} - ∣ x ∣ - 6}{4 x + 1} : \frac{4 ∣ x ∣ ^{2} - 13 ∣ x ∣ + 3}{4 x + 1}

\frac{4 ∣ x ∣ ^{2} - 13 ∣ x ∣ + 3}{4 x + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

4 ∣ x ∣^{2} - 13 ∣ x ∣ + 3 = 0

Solve

4 ∣ x ∣^{2} - 13 ∣ x ∣ + 3 = 0 : x = - \frac{1}{4}, x = \frac{1}{4}, x = - 3, x = 3

x = - \frac{1}{4}, x = \frac{1}{4}, x = - 3, x = 3

Verify Solutions

Find undefined (singularity) points:

x = - \frac{1}{4}

Since the equation is undefined for:

- \frac{1}{4}

x = \frac{1}{4}, x = - 3, x = 3

p = \frac{( y + 2 b )}{y}

\frac{( 3 x - 5 )}{( x + 5 )} = 1

\frac{( n + 3 ) !}{( n + 1 ) !} = 30

n, v = (\frac{1}{n}) \frac{r ^{2}}{3} s \frac{1}{2}

x = \frac{4}{5 \cdot ( x + 10 )}

What is the answer to (((2|x|-3)^2-|x|-6))/((4x+1))=0 ?
The answer to (((2|x|-3)^2-|x|-6))/((4x+1))=0 is x= 1/4 ,x=-3,x=3
Solve for x: (((2|x|-3)^2-|x|-6))/((4x+1))=0
The solution is x= 1/4 ,x=-3,x=3