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Popular >

((j+4))/((j+5))-((j+2))/((j+3))= 1/24

Solution

\frac{( j + 4 )}{( j + 5 )} - \frac{( j + 2 )}{( j + 3 )} = \frac{1}{24}

Solution

j = 3, j = - 11

Solution steps

\frac{( j + 4 )}{( j + 5 )} - \frac{( j + 2 )}{( j + 3 )} = \frac{1}{24}

Multiply by LCM

24 (j + 4) (j + 3) - 24 (j + 2) (j + 5) = (j + 5) (j + 3)

Solve

24 (j + 4) (j + 3) - 24 (j + 2) (j + 5) = (j + 5) (j + 3) : j = 3, j = - 11

j = 3, j = - 11

Verify Solutions

Find undefined (singularity) points:

j = - 5, j = - 3

Combine undefined points with solutions:

j = 3, j = - 11

Popular Examples

4/x+3/((x^2+x))=0

\frac{4}{x} + \frac{3}{( x ^{2} + x )} = 0

\frac{x}{3} + \frac{3}{x} = \frac{41}{4}

((x^2-2x)(2x-2)-9(2x-2))/((x^2-2x))=0

\frac{( x ^{2} - 2 x ) ( 2 x - 2 ) - 9 ( 2 x - 2 )}{( x ^{2} - 2 x )} = 0

solvefor x, 4/x-5/y =2 solve for

x, \frac{4}{x} - \frac{5}{y} = 2

(51)/(2-3x)= 4/3

\frac{51}{2 - 3 x} = \frac{4}{3}

Frequently Asked Questions (FAQ)

What is the answer to ((j+4))/((j+5))-((j+2))/((j+3))= 1/24 ?
The answer to ((j+4))/((j+5))-((j+2))/((j+3))= 1/24 is j=3,j=-11
Solve for j: ((j+4))/((j+5))-((j+2))/((j+3))= 1/24
The solution is j=3,j=-11