What is the answer to (((2x-3)(x-1)-(2x^2+x+1)))/((2-x))= 7/2 ?

The answer to (((2x-3)(x-1)-(2x^2+x+1)))/((2-x))= 7/2 is x=-2

Popular >

(((2x-3)(x-1)-(2x^2+x+1)))/((2-x))= 7/2

\frac{( ( 2 x - 3 ) ( x - 1 ) - ( 2 x ^{2} + x + 1 ) )}{( 2 - x )} = \frac{7}{2}

x = - 2

Solution steps

\frac{( ( 2 x - 3 ) ( x - 1 ) - ( 2 x ^{2} + x + 1 ) )}{( 2 - x )} = \frac{7}{2}

Cross multiply

- 12 x + 4 = 14 - 7 x

Move

4

to the right side

- 12 x = - 7 x + 10

Move

7 x

to the left side

- 5 x = 10

Divide both sides by

- 5

x = - 2

Verify Solutions

Find undefined (singularity) points:

x = 2

Combine undefined points with solutions:

x = - 2

\frac{1}{x} = \frac{1}{4} + \frac{1}{6}

2 (\frac{x + 1}{x})^{2} - 3 (\frac{x - 1}{x}) - 8 = 0

\frac{1}{( x - 2 )} + \frac{1}{( x + 3 )} + \frac{1}{( x + 4 )} = 0

\frac{1.1}{3} = \frac{4}{x}

\frac{t}{( t + 3 )} = \frac{11}{5}

What is the answer to (((2x-3)(x-1)-(2x^2+x+1)))/((2-x))= 7/2 ?
The answer to (((2x-3)(x-1)-(2x^2+x+1)))/((2-x))= 7/2 is x=-2
Solve for x: (((2x-3)(x-1)-(2x^2+x+1)))/((2-x))= 7/2
The solution is x=-2