What is the answer to (x^3-8x^3)/((x+2)^3)=7 ?

The answer to (x^3-8x^3)/((x+2)^3)=7 is x=-1,x=-1+sqrt(3)i,x=-1-sqrt(3)i

Solve for x: (x^3-8x^3)/((x+2)^3)=7

The solution is x=-1,x=-1+sqrt(3)i,x=-1-sqrt(3)i

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\frac{x ^{3} - 8 x ^{3}}{( x + 2 ) ^{3}} = 7

x = - 1, x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

\frac{x ^{3} - 8 x ^{3}}{( x + 2 ) ^{3}} = 7

Simplify

\frac{x ^{3} - 8 x ^{3}}{( x + 2 ) ^{3}} : - \frac{7 x ^{3}}{( x + 2 ) ^{3}}

- \frac{7 x ^{3}}{( x + 2 ) ^{3}} = 7

Multiply both sides by

(x + 2)^{3}

- 7 x^{3} = 7 (x + 2)^{3}

Solve

- 7 x^{3} = 7 (x + 2)^{3} : x = - 1, x = - 1 + 3 i, x = - 1 - 3 i

x = - 1, x = - 1 + 3 i, x = - 1 - 3 i

Verify Solutions

Find undefined (singularity) points:

x = - 2

Combine undefined points with solutions:

x = - 1, x = - 1 + 3 i, x = - 1 - 3 i

x + \frac{1}{x} = 5, x^{2} + \frac{1}{( x ^{2} )} =, x^{3} + \frac{1}{( x ^{3} )}

\frac{x - 1}{4} = \frac{1}{4 - x}

\frac{( 5 + x )}{( 100 + x )} = 0.24

\frac{x}{2 ^{2 x + 3}} = 8^{5 + x}

∣ x ∣ + \frac{( 4 - x ^{2} )}{x} = \frac{4}{x}

What is the answer to (x^3-8x^3)/((x+2)^3)=7 ?
The answer to (x^3-8x^3)/((x+2)^3)=7 is x=-1,x=-1+sqrt(3)i,x=-1-sqrt(3)i
Solve for x: (x^3-8x^3)/((x+2)^3)=7
The solution is x=-1,x=-1+sqrt(3)i,x=-1-sqrt(3)i