What are the solutions to the equation u^2+3u-4=0 ?

The solutions to the equation u^2+3u-4=0 are u=1,u=-4

Find the zeros of u^2+3u-4=0

The zeros of u^2+3u-4=0 are u=1,u=-4

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u^{2} + 3 u - 4 = 0

u = 1, u = - 4

Solution steps

u^{2} + 3 u - 4 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 4) = 5

u_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 3 + 5}{2 \cdot 1}, u_{2} = \frac{- 3 - 5}{2 \cdot 1}

u = \frac{- 3 + 5}{2 \cdot 1} : 1

u = \frac{- 3 - 5}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

u = 1, u = - 4

9 x^{2} + 12 x + 4 = 0

2 x^{2} - 8 x + 4 = 0

- 3 ∣ p ∣ = - 12

- 4 x - 14 - 9 x = - 13 x - 7 - 6

60 x^{3} + 50 x^{5}

What are the solutions to the equation u^2+3u-4=0 ?
The solutions to the equation u^2+3u-4=0 are u=1,u=-4
Find the zeros of u^2+3u-4=0
The zeros of u^2+3u-4=0 are u=1,u=-4