What are the solutions to the equation -6x^2-2-3x=-8 ?

The solutions to the equation -6x^2-2-3x=-8 are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4

Find the zeros of -6x^2-2-3x=-8

The zeros of -6x^2-2-3x=-8 are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4

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- 6 x^{2} - 2 - 3 x = - 8

x = - \frac{1 + 17}{4}, x = \frac{17 - 1}{4}

Decimal Notation

x = - 1.28077 \dots, x = 0.78077 \dots

Solution steps

- 6 x^{2} - 2 - 3 x = - 8

Move

8

to the left side

- 6 x^{2} - 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 6 ) \cdot 6}{2 ( - 6 )}

(- 3)^{2} - 4 (- 6) \cdot 6 = 317

x_{1, 2} = \frac{- ( - 3 ) \pm 3 17}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 17}{2 ( - 6 )}, x_{2} = \frac{- ( - 3 ) - 3 17}{2 ( - 6 )}

x = \frac{- ( - 3 ) + 3 17}{2 ( - 6 )} : - \frac{1 + 17}{4}

x = \frac{- ( - 3 ) - 3 17}{2 ( - 6 )} : \frac{17 - 1}{4}

The solutions to the quadratic equation are:

x = - \frac{1 + 17}{4}, x = \frac{17 - 1}{4}

- 2 x^{2} + 8 x + 7 = 0

- 1 \leq y \leq 3

\frac{8 x h + 4 h ^{2} - 2 h}{h}

t - 2.79 \leq - 4.79

- 8 x - (8 x) = - 48

What are the solutions to the equation -6x^2-2-3x=-8 ?
The solutions to the equation -6x^2-2-3x=-8 are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4
Find the zeros of -6x^2-2-3x=-8
The zeros of -6x^2-2-3x=-8 are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4