What are the solutions to the equation -2x^2+8x+7=0 ?

The solutions to the equation -2x^2+8x+7=0 are x=-(-4+sqrt(30))/2 ,x=(4+sqrt(30))/2

Find the zeros of -2x^2+8x+7=0

The zeros of -2x^2+8x+7=0 are x=-(-4+sqrt(30))/2 ,x=(4+sqrt(30))/2

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- 2 x^{2} + 8 x + 7 = 0

x = - \frac{- 4 + 30}{2}, x = \frac{4 + 30}{2}

Decimal Notation

x = - 0.73861 \dots, x = 4.73861 \dots

Solution steps

- 2 x^{2} + 8 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) \cdot 7}{2 ( - 2 )}

8^{2} - 4 (- 2) \cdot 7 = 230

x_{1, 2} = \frac{- 8 \pm 2 30}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 30}{2 ( - 2 )}, x_{2} = \frac{- 8 - 2 30}{2 ( - 2 )}

x = \frac{- 8 + 2 30}{2 ( - 2 )} : - \frac{- 4 + 30}{2}

x = \frac{- 8 - 2 30}{2 ( - 2 )} : \frac{4 + 30}{2}

The solutions to the quadratic equation are:

x = - \frac{- 4 + 30}{2}, x = \frac{4 + 30}{2}

- 1 \leq y \leq 3

\frac{8 x h + 4 h ^{2} - 2 h}{h}

t - 2.79 \leq - 4.79

- 8 x - (8 x) = - 48

\frac{c - 1}{4} + \frac{2 c + 3}{6} = c - 1

What are the solutions to the equation -2x^2+8x+7=0 ?
The solutions to the equation -2x^2+8x+7=0 are x=-(-4+sqrt(30))/2 ,x=(4+sqrt(30))/2
Find the zeros of -2x^2+8x+7=0
The zeros of -2x^2+8x+7=0 are x=-(-4+sqrt(30))/2 ,x=(4+sqrt(30))/2