What is the answer to (x^2-2x)/((x-1)^2)=0 ?

The answer to (x^2-2x)/((x-1)^2)=0 is x=2,x=0

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(x^2-2x)/((x-1)^2)=0

\frac{x ^{2} - 2 x}{( x - 1 ) ^{2}} = 0

x = 2, x = 0

Solution steps

\frac{x ^{2} - 2 x}{( x - 1 ) ^{2}} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} - 2 x = 0

Solve

x^{2} - 2 x = 0 : x = 2, x = 0

x = 2, x = 0

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = 2, x = 0

\frac{6 + 5}{x} = \frac{71}{4}

k = \frac{( a \cdot v ^{2} )}{( b + x ^{2} )}

\frac{2 x + 1}{3 x + 2} = 2

a, \frac{1}{a} + \frac{1}{b} + \frac{1}{c} = \frac{29}{72}

m^{- 2} = \frac{1}{9}

What is the answer to (x^2-2x)/((x-1)^2)=0 ?
The answer to (x^2-2x)/((x-1)^2)=0 is x=2,x=0
Solve for x: (x^2-2x)/((x-1)^2)=0
The solution is x=2,x=0