What is the answer to (c-1)/4+(2c+3)/6 =c-1 ?

The answer to (c-1)/4+(2c+3)/6 =c-1 is c=3

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(c-1)/4+(2c+3)/6 =c-1

\frac{c - 1}{4} + \frac{2 c + 3}{6} = c - 1

c = 3

Solution steps

\frac{c - 1}{4} + \frac{2 c + 3}{6} = c - 1

Multiply by LCM

3 (c - 1) + 2 (2 c + 3) = 12 c - 12

Expand

3 (c - 1) + 2 (2 c + 3) : 7 c + 3

7 c + 3 = 12 c - 12

Move

3

to the right side

7 c = 12 c - 15

Move

12 c

to the left side

- 5 c = - 15

Divide both sides by

- 5

c = 3

- 5 x < 10

- 96 z^{2} = - 48

x^{2} + 6 x = 2

3 x^{2} + 10 x + 6 = 0

4 a^{2} - a - 5

What is the answer to (c-1)/4+(2c+3)/6 =c-1 ?
The answer to (c-1)/4+(2c+3)/6 =c-1 is c=3
Solve for c: (c-1)/4+(2c+3)/6 =c-1
The solution is c=3