What is the answer to solvefor u,f=(x^4)/u*((x+2))/v ?

The answer to solvefor u,f=(x^4)/u*((x+2))/v is u=(x^4(x+2))/(vf);\quad f\ne 0

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solvefor u,f=(x^4)/u*((x+2))/v

solve for

u, f = \frac{x ^{4}}{u} \cdot \frac{( x + 2 )}{v}

u = \frac{x ^{4} ( x + 2 )}{v f}; f \neq = 0

Solution steps

f = \frac{x ^{4}}{u} \cdot \frac{( x + 2 )}{v}

Simplify

\frac{x ^{4}}{u} \cdot \frac{x + 2}{v} : \frac{x ^{4} ( x + 2 )}{uv}

f = \frac{x ^{4} ( x + 2 )}{uv}

Multiply both sides by

u

f u = \frac{x ^{4} ( x + 2 )}{v}

Divide both sides by

f; f \neq = 0

u = \frac{x ^{4} ( x + 2 )}{v f}; f \neq = 0

0.2 = \frac{- 198}{n ^{3} - n}

\frac{y ^{2} - 5}{3 \cdot y} = \frac{- 1}{3}

\frac{3}{( x - 2 )} - \frac{2}{( x - 3 )} = \frac{4}{( x - 3 )} - \frac{3}{( x - 1 )}

(0.5)^{3} = (y)^{- 3}

x, (x) y = \frac{1}{( 2 x + 1 )}

What is the answer to solvefor u,f=(x^4)/u*((x+2))/v ?
The answer to solvefor u,f=(x^4)/u*((x+2))/v is u=(x^4(x+2))/(vf);\quad f\ne 0