What are the solutions to the equation x^2+6x=2 ?

The solutions to the equation x^2+6x=2 are x=-3+sqrt(11),x=-3-sqrt(11)

Find the zeros of x^2+6x=2

The zeros of x^2+6x=2 are x=-3+sqrt(11),x=-3-sqrt(11)

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x^{2} + 6 x = 2

x = - 3 + 11, x = - 3 - 11

Decimal Notation

x = 0.31662 \dots, x = - 6.31662 \dots

Solution steps

x^{2} + 6 x = 2

Move

2

to the left side

x^{2} + 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 2) = 211

x_{1, 2} = \frac{- 6 \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 11}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 11}{2 \cdot 1}

x = \frac{- 6 + 2 11}{2 \cdot 1} : - 3 + 11

x = \frac{- 6 - 2 11}{2 \cdot 1} : - 3 - 11

The solutions to the quadratic equation are:

x = - 3 + 11, x = - 3 - 11

3 x^{2} + 10 x + 6 = 0

4 a^{2} - a - 5

(5 x + 2) (x + 1) = 1

3 (3)

(x - 1)^{2} = 25

What are the solutions to the equation x^2+6x=2 ?
The solutions to the equation x^2+6x=2 are x=-3+sqrt(11),x=-3-sqrt(11)
Find the zeros of x^2+6x=2
The zeros of x^2+6x=2 are x=-3+sqrt(11),x=-3-sqrt(11)