What is the answer to 8=((250k))/((t_{1)-250k)} ?

The answer to 8=((250k))/((t_{1)-250k)} is t_{1}=(125k)/4+250k

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8=((250k))/((t_{1)-250k)}

8 = \frac{( 250 k )}{( t _{1} - 250 k )}

t_{1} = \frac{125 k}{4} + 250 k

Solution steps

8 = \frac{( 250 k )}{( t _{1} - 250 k )}

Simplify

\frac{( 250 k )}{( t _{1} - 250 k )} : \frac{250 k}{t _{1} - 250 k}

8 = \frac{250 k}{t _{1} - 250 k}

Multiply both sides by

t_{1} - 250 k

8 (t_{1} - 250 k) = 250 k

Divide both sides by

8

t_{1} - 250 k = \frac{125 k}{4}

Move

250 k

to the right side

t_{1} = \frac{125 k}{4} + 250 k

0.0507 = \frac{( \frac{2.64}{m} )}{( \frac{2.64}{m} + \frac{32}{74} )}

\frac{x + 1}{x - 3} = \frac{0 x ^{3} + 1}{x ^{3}}

\frac{x ^{2} + 1}{x - 5 ( x + \frac{1}{x} ) + 8} = 0

\frac{y ^{2} - 5}{3 y} = - 13

x, \frac{1}{x} + \frac{3}{y} = 1

What is the answer to 8=((250k))/((t_{1)-250k)} ?
The answer to 8=((250k))/((t_{1)-250k)} is t_{1}=(125k)/4+250k