What are the solutions to the equation 12x^2-5x-3=0 ?

The solutions to the equation 12x^2-5x-3=0 are x= 3/4 ,x=-1/3

Find the zeros of 12x^2-5x-3=0

The zeros of 12x^2-5x-3=0 are x= 3/4 ,x=-1/3

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12 x^{2} - 5 x - 3 = 0

x = \frac{3}{4}, x = - \frac{1}{3}

Solution steps

12 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 12 ( - 3 )}{2 \cdot 12}

(- 5)^{2} - 4 \cdot 12 (- 3) = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 12}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 12}

x = \frac{- ( - 5 ) + 13}{2 \cdot 12} : \frac{3}{4}

x = \frac{- ( - 5 ) - 13}{2 \cdot 12} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{1}{3}

3 (x - 4)^{2} + 15 (x - 4)

9 x - 2 > 43

2^{2} \cdot 4^{2}

e^{- 0^{2}}

4 x^{2} + 20 x + 9 = 0

What are the solutions to the equation 12x^2-5x-3=0 ?
The solutions to the equation 12x^2-5x-3=0 are x= 3/4 ,x=-1/3
Find the zeros of 12x^2-5x-3=0
The zeros of 12x^2-5x-3=0 are x= 3/4 ,x=-1/3