What is the answer to x^{-4}-6x^{-2}+8=0 ?

The answer to x^{-4}-6x^{-2}+8=0 is x= 1/(sqrt(2)),x=-1/(sqrt(2)),x= 1/2 ,x=-1/2

Solve for x: x^{-4}-6x^{-2}+8=0

The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2)),x= 1/2 ,x=-1/2

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x^{- 4} - 6 x^{- 2} + 8 = 0

x = \frac{1}{2}, x = - \frac{1}{2}, x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots, x = 0.5, x = - 0.5

Solution steps

x^{- 4} - 6 x^{- 2} + 8 = 0

Refine

\frac{1}{x ^{4}} - \frac{6}{x ^{2}} + 8 = 0

Multiply by LCM

1 - 6 x^{2} + 8 x^{4} = 0

Solve

1 - 6 x^{2} + 8 x^{4} = 0 : x = \frac{1}{2}, x = - \frac{1}{2}, x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}, x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{1}{2}, x = - \frac{1}{2}, x = \frac{1}{2}, x = - \frac{1}{2}

\frac{( x ) ^{2}}{( ( \frac{4}{5} ) ^{- 4} )} = (\frac{1}{x})^{2}

\frac{1}{( x + 1 )} + \frac{3}{( x + 4 )} = \frac{4}{( x + 3 )}

x, \frac{1}{( 2 x )} + \frac{1}{( 3 y )} = 2

\frac{\frac{9}{5}}{x} = \frac{( \frac{3}{2} + \frac{1}{4} )}{( 1 + \frac{7}{9} )}

\frac{a}{x - 51} = 3

What is the answer to x^{-4}-6x^{-2}+8=0 ?
The answer to x^{-4}-6x^{-2}+8=0 is x= 1/(sqrt(2)),x=-1/(sqrt(2)),x= 1/2 ,x=-1/2
Solve for x: x^{-4}-6x^{-2}+8=0
The solution is x= 1/(sqrt(2)),x=-1/(sqrt(2)),x= 1/2 ,x=-1/2