What is the answer to 2((x^2+1}{x^2})-3(\frac{x-1)/x)-4=0 ?

The answer to 2((x^2+1}{x^2})-3(\frac{x-1)/x)-4=0 is x=-2/5 ,x=1

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2((x^2+1}{x^2})-3(\frac{x-1)/x)-4=0

2 (\frac{x ^{2} + 1}{x ^{2}}) - 3 (\frac{x - 1}{x}) - 4 = 0

x = - \frac{2}{5}, x = 1

Decimal Notation

x = - 0.4, x = 1

Solution steps

2 (\frac{x ^{2} + 1}{x ^{2}}) - 3 (\frac{x - 1}{x}) - 4 = 0

Multiply by LCM

2 (x^{2} + 1) - 3 x (x - 1) - 4 x^{2} = 0

Solve

2 (x^{2} + 1) - 3 x (x - 1) - 4 x^{2} = 0 : x = - \frac{2}{5}, x = 1

x = - \frac{2}{5}, x = 1

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{2}{5}, x = 1

x, (\frac{1}{x}) - (\frac{1}{y}) - 2 = 0

y, 3 x^{2} y^{4} = 5 x^{3} y^{- 3} z^{2}

\frac{( 1 + x ^{4} + x ^{8} )}{x ^{4}} = 4

\frac{2 ( x + 1 )}{3 + 4 ( x - 2 )} = \frac{x}{2 + 5}

\frac{3 x - 2}{x} = \frac{59 x ^{2} - 4}{x ^{2}}

What is the answer to 2((x^2+1}{x^2})-3(\frac{x-1)/x)-4=0 ?
The answer to 2((x^2+1}{x^2})-3(\frac{x-1)/x)-4=0 is x=-2/5 ,x=1
Solve for x: 2((x^2+1}{x^2})-3(\frac{x-1)/x)-4=0
The solution is x=-2/5 ,x=1