What is the answer to 0.3(x+1)= 1/(2(x-1)) ?

The answer to 0.3(x+1)= 1/(2(x-1)) is x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))

Solve for x: 0.3(x+1)= 1/(2(x-1))

The solution is x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))

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0.3 (x + 1) = \frac{1}{2 ( x - 1 )}

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

Decimal Notation

x = 1.63299 \dots, x = - 1.63299 \dots

Solution steps

0.3 (x + 1) = \frac{1}{2 ( x - 1 )}

Multiply both sides by

10

3 (x + 1) = \frac{5}{x - 1}

Multiply both sides by

x - 1

3 (x + 1) (x - 1) = 5

Solve

3 (x + 1) (x - 1) = 5 : x = \frac{2 2}{3}, x = - \frac{2 2}{3}

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

Verify Solutions

Find undefined (singularity) points:

x = 1

Combine undefined points with solutions:

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

\frac{6}{( x - 2 )} = \frac{3 + ( 3 x )}{( x - 2 )}

\frac{4 x}{5 + x + 2} = \frac{x}{2 + x + 5}

\frac{2}{( x + 2 )} + \frac{3}{( x - 1 )} = \frac{1}{( x + 2 )}

x^{2} + \frac{1}{( x ^{2} )} + x - \frac{1}{x} - 14 = 0

x^{2} + \frac{1}{( x ^{2} )} = x^{8} + \frac{1}{( x ^{8} )}

What is the answer to 0.3(x+1)= 1/(2(x-1)) ?
The answer to 0.3(x+1)= 1/(2(x-1)) is x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))
Solve for x: 0.3(x+1)= 1/(2(x-1))
The solution is x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))