What is the answer to x^2+1/((x^2))=x^8+1/((x^8)) ?

The answer to x^2+1/((x^2))=x^8+1/((x^8)) is x=1,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+1/((x^2))=x^8+1/((x^8))

x^{2} + \frac{1}{( x ^{2} )} = x^{8} + \frac{1}{( x ^{8} )}

x = 1, x = - 1

Solution steps

x^{2} + \frac{1}{( x ^{2} )} = x^{8} + \frac{1}{( x ^{8} )}

Multiply by LCM

x^{10} + x^{6} = x^{16} + 1

Solve

x^{10} + x^{6} = x^{16} + 1 : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 1, x = - 1

\frac{( x - 2 )}{( x + 1 )} = \frac{1}{2}

\frac{3}{5} + \frac{3}{( 2 x - 1 )} = 0

0 = \frac{1}{2 x ^{2}}

2 \frac{x}{x} - 4 + \frac{1}{x} - 2 + \frac{2}{x ^{2}} - 6 x + 8 = 0

\frac{6 x}{9 x + 16} = 12

What is the answer to x^2+1/((x^2))=x^8+1/((x^8)) ?
The answer to x^2+1/((x^2))=x^8+1/((x^8)) is x=1,x=-1
Solve for x: x^2+1/((x^2))=x^8+1/((x^8))
The solution is x=1,x=-1