What is the answer to (n-1)/(n^2)= 1/n+(5n+30)/(n^2) ?

The answer to (n-1)/(n^2)= 1/n+(5n+30)/(n^2) is n=-31/5

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(n-1)/(n^2)= 1/n+(5n+30)/(n^2)

\frac{n - 1}{n ^{2}} = \frac{1}{n} + \frac{5 n + 30}{n ^{2}}

n = - \frac{31}{5}

Decimal Notation

n = - 6.2

Solution steps

\frac{n - 1}{n ^{2}} = \frac{1}{n} + \frac{5 n + 30}{n ^{2}}

Multiply by LCM

n - 1 = 6 n + 30

Move

1

to the right side

n = 6 n + 31

Move

6 n

to the left side

- 5 n = 31

Divide both sides by

- 5

n = - \frac{31}{5}

Verify Solutions

Find undefined (singularity) points:

n = 0

Combine undefined points with solutions:

n = - \frac{31}{5}

0.562 = \frac{a}{( a + 42 )}

\frac{lo g _{10} ( 1 )}{2 x} = 4 x^{2}

[\frac{x + 1}{x}]^{2} = \frac{4 + 3}{2 \cdot [ x - \frac{1}{x} ]}

\frac{61}{2} = \frac{11}{2 + n}

\frac{4 x}{x + 1} = \frac{10}{3}

What is the answer to (n-1)/(n^2)= 1/n+(5n+30)/(n^2) ?
The answer to (n-1)/(n^2)= 1/n+(5n+30)/(n^2) is n=-31/5
Solve for n: (n-1)/(n^2)= 1/n+(5n+30)/(n^2)
The solution is n=-31/5