What is the answer to (x)= 1/(4*x^2-x+9) ?

The answer to (x)= 1/(4*x^2-x+9) is x\approx 0.11187…

Solve for x: (x)= 1/(4*x^2-x+9)

The solution is x\approx 0.11187…

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(x) = \frac{1}{4 \cdot x ^{2} - x + 9}

x \approx 0.11187 \dots

Solution steps

(x) = \frac{1}{4 x ^{2} - x + 9}

Multiply both sides by

4 x^{2} - x + 9

x (4 x^{2} - x + 9) = 1

Solve

x (4 x^{2} - x + 9) = 1 : x \approx 0.11187 \dots

x \approx 0.11187 \dots

\frac{x ^{2} - 1}{x} = \frac{2 x ^{6} - 1}{x ^{3}}

x^{2} - 2 x = \frac{1}{4 - 2 x}

a, (t) = \frac{1}{( ( cos ( t ) + tan ( t ) ) ^{2} )}

x + 15 = \frac{2}{5 + ( x + 15 ) 0.4 x}

\frac{x - 2}{7 x} = 210

What is the answer to (x)= 1/(4*x^2-x+9) ?
The answer to (x)= 1/(4*x^2-x+9) is x\approx 0.11187…
Solve for x: (x)= 1/(4*x^2-x+9)
The solution is x\approx 0.11187…