What is the answer to a= 1/(2(1+x)) ?

The answer to a= 1/(2(1+x)) is x= 1/(a*2)-1;\quad a\ne 0

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a= 1/(2(1+x))

a = \frac{1}{2 ( 1 + x )}

x = \frac{1}{a \cdot 2} - 1; a \neq = 0

Solution steps

a = \frac{1}{2 ( 1 + x )}

Multiply both sides by

2 (1 + x)

a \cdot 2 (1 + x) = 1

Divide both sides by

a \cdot 2; a \neq = 0

1 + x = \frac{1}{a \cdot 2}; a \neq = 0

Move

1

to the right side

x = \frac{1}{a \cdot 2} - 1; a \neq = 0

\frac{6}{x} - \frac{1}{4} = - \frac{1}{2}

a, \frac{2}{a} + \frac{3}{b} = 1

\frac{30}{x} = 0.15

\frac{5 x ^{2} + 1}{( x ^{2} ) - 5 ( x + \frac{1}{x} ) + 8} = 0

\frac{270}{( x - 12 )} - \frac{270}{x} = \frac{3}{4}

What is the answer to a= 1/(2(1+x)) ?
The answer to a= 1/(2(1+x)) is x= 1/(a*2)-1;\quad a\ne 0