What is the answer to ((x^2+1}{x^2})-4(\frac{x-1)/x)-14=0 ?

The answer to ((x^2+1}{x^2})-4(\frac{x-1)/x)-14=0 is x=-(-2+sqrt(21))/(17),x=(2+sqrt(21))/(17)

Solve for x: ((x^2+1}{x^2})-4(\frac{x-1)/x)-14=0

The solution is x=-(-2+sqrt(21))/(17),x=(2+sqrt(21))/(17)

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(\frac{x ^{2} + 1}{x ^{2}}) - 4 (\frac{x - 1}{x}) - 14 = 0

x = - \frac{- 2 + 21}{17}, x = \frac{2 + 21}{17}

Decimal Notation

x = - 0.15191 \dots, x = 0.38721 \dots

Solution steps

(\frac{x ^{2} + 1}{x ^{2}}) - 4 (\frac{x - 1}{x}) - 14 = 0

Multiply by LCM

- 13 x^{2} - 4 x (x - 1) + 1 = 0

Solve

- 13 x^{2} - 4 x (x - 1) + 1 = 0 : x = - \frac{- 2 + 21}{17}, x = \frac{2 + 21}{17}

x = - \frac{- 2 + 21}{17}, x = \frac{2 + 21}{17}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = - \frac{- 2 + 21}{17}, x = \frac{2 + 21}{17}

f (n) = \frac{w ^{n + 1}}{w ^{2 n}}

\frac{x ^{2} - 1}{2 x - 4} = 0

\frac{( ( 2 n - 1 ) ! )}{( ( 2 n - 3 ) ! )} = 120

(\frac{x + 1}{x})^{2} + 5 (\frac{x + 1}{x}) + 4 = 0

\frac{- 5 + 3}{4 ∣ 1 - x ∣} = \frac{7}{3}

What is the answer to ((x^2+1}{x^2})-4(\frac{x-1)/x)-14=0 ?
The answer to ((x^2+1}{x^2})-4(\frac{x-1)/x)-14=0 is x=-(-2+sqrt(21))/(17),x=(2+sqrt(21))/(17)
Solve for x: ((x^2+1}{x^2})-4(\frac{x-1)/x)-14=0
The solution is x=-(-2+sqrt(21))/(17),x=(2+sqrt(21))/(17)