What is the answer to (x^2-1)/(2x-4)=0 ?

The answer to (x^2-1)/(2x-4)=0 is x=1,x=-1

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(x^2-1)/(2x-4)=0

\frac{x ^{2} - 1}{2 x - 4} = 0

x = 1, x = - 1

Solution steps

\frac{x ^{2} - 1}{2 x - 4} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x^{2} - 1 = 0

Solve

x^{2} - 1 = 0 : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions

Find undefined (singularity) points:

x = 2

Combine undefined points with solutions:

x = 1, x = - 1

\frac{( ( 2 n - 1 ) ! )}{( ( 2 n - 3 ) ! )} = 120

(\frac{x + 1}{x})^{2} + 5 (\frac{x + 1}{x}) + 4 = 0

\frac{- 5 + 3}{4 ∣ 1 - x ∣} = \frac{7}{3}

\frac{( x + 1 )}{x} + ∣ x + 1 ∣ = \frac{( ( x + 1 ) ^{2} )}{∣ x ∣}

f^{- 1} (9) = 2, f^{- 1} (- 8)

What is the answer to (x^2-1)/(2x-4)=0 ?
The answer to (x^2-1)/(2x-4)=0 is x=1,x=-1
Solve for x: (x^2-1)/(2x-4)=0
The solution is x=1,x=-1