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Popular >

|((x+1))/x |+|x+1|=(((x+1)^2))/(|x|)

Solution

\frac{( x + 1 )}{x} + ∣ x + 1 ∣ = \frac{( ( x + 1 ) ^{2} )}{∣ x ∣}

Solution

x = - 1 or x \geq 0

Solution steps

\frac{( x + 1 )}{x} + ∣ x + 1 ∣ = \frac{( ( x + 1 ) ^{2} )}{∣ x ∣}

Simplify

\frac{∣ x + 1 ∣}{∣ x ∣} + ∣ x + 1 ∣ = \frac{( x + 1 ) ^{2}}{∣ x ∣}

Multiply both sides by

∣ x ∣

∣ x + 1 ∣ + ∣ x + 1 ∣ ∣ x ∣ = (x + 1)^{2}

Solve

∣ x + 1 ∣ + ∣ x + 1 ∣ ∣ x ∣ = (x + 1)^{2} : x = - 1 or x \geq 0

x = - 1 or x \geq 0

Popular Examples

f^{-1}(9)=2,f^{-1}(-8)

f^{- 1} (9) = 2, f^{- 1} (- 8)

x/((x-2))-((x-2))/x = 5/2

\frac{x}{( x - 2 )} - \frac{( x - 2 )}{x} = \frac{5}{2}

(-3)/((x-2)^2)=0

\frac{- 3}{( x - 2 ) ^{2}} = 0

(x+x^2+x^3)+(1/x+1/((x^2))+1/((x^3)))=28

(x + x^{2} + x^{3}) + (\frac{1}{x} + \frac{1}{( x ^{2} )} + \frac{1}{( x ^{3} )}) = 28

270= n/(2[2x^{10)+(n-1)5]}

270 = \frac{n}{2 [ 2 x ^{10} + ( n - 1 ) 5 ]}

Frequently Asked Questions (FAQ)

What is the answer to |((x+1))/x |+|x+1|=(((x+1)^2))/(|x|) ?
The answer to |((x+1))/x |+|x+1|=(((x+1)^2))/(|x|) is x=-1\lor x>= 0
Solve for x: |((x+1))/x |+|x+1|=(((x+1)^2))/(|x|)
The solution is x=-1\lor x>= 0