What are the solutions to the equation r^2+5r+4=0 ?

The solutions to the equation r^2+5r+4=0 are r=-1,r=-4

Find the zeros of r^2+5r+4=0

The zeros of r^2+5r+4=0 are r=-1,r=-4

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r^{2} + 5 r + 4 = 0

r = - 1, r = - 4

Solution steps

r^{2} + 5 r + 4 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 4 = 3

r_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 5 + 3}{2 \cdot 1}, r_{2} = \frac{- 5 - 3}{2 \cdot 1}

r = \frac{- 5 + 3}{2 \cdot 1} : - 1

r = \frac{- 5 - 3}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

r = - 1, r = - 4

∣ x ∣ = 3

- \frac{3}{8 ^{2}}

4 x^{2} = 6 - 5 x

ln (2.2)

2 x^{5} y \cdot 3 x^{2} y

What are the solutions to the equation r^2+5r+4=0 ?
The solutions to the equation r^2+5r+4=0 are r=-1,r=-4
Find the zeros of r^2+5r+4=0
The zeros of r^2+5r+4=0 are r=-1,r=-4