What is the answer to solvefor a,a-c=2((a+b))/a ?

The answer to solvefor a,a-c=2((a+b))/a is a=(c+2+sqrt((-c-2)^2+8b))/2 ,a=(c+2-sqrt((-c-2)^2+8b))/2

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solvefor a,a-c=2((a+b))/a

solve for

a, a - c = 2 \frac{( a + b )}{a}

a = \frac{c + 2 + ( - c - 2 ) ^{2} + 8 b}{2}, a = \frac{c + 2 - ( - c - 2 ) ^{2} + 8 b}{2}

Solution steps

a - c = 2 \cdot \frac{( a + b )}{a}

Simplify

2 \cdot \frac{a + b}{a} : \frac{2 ( a + b )}{a}

a - c = \frac{2 ( a + b )}{a}

Multiply both sides by

a

a^{2} - c a = 2 (a + b)

Solve

a^{2} - c a = 2 (a + b) : a = \frac{c + 2 + ( - c - 2 ) ^{2} + 8 b}{2}, a = \frac{c + 2 - ( - c - 2 ) ^{2} + 8 b}{2}

a = \frac{c + 2 + ( - c - 2 ) ^{2} + 8 b}{2}, a = \frac{c + 2 - ( - c - 2 ) ^{2} + 8 b}{2}

e^{l} n x = \frac{x ^{1}}{x}

(\frac{3}{4 x + 1})^{3} - (x + 2)^{3} + (0.25 x + 1)^{3} = 0

\frac{3}{4 x ^{2} - x - 1} = 0

x, \frac{( d ^{2} \cdot y )}{( d \cdot x ^{2} )} + y = 0

x, g^{- 1} (2) g = \frac{20}{x} + 1

What is the answer to solvefor a,a-c=2((a+b))/a ?
The answer to solvefor a,a-c=2((a+b))/a is a=(c+2+sqrt((-c-2)^2+8b))/2 ,a=(c+2-sqrt((-c-2)^2+8b))/2