What is the answer to a(x)= x/((x+2)),b(x)-2^{-x} ?

The answer to a(x)= x/((x+2)),b(x)-2^{-x} is x=0,x=-(2a-1)/a ;\quad a\ne 0

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a(x)= x/((x+2)),b(x)-2^{-x}

a (x) = \frac{x}{( x + 2 )}, b (x) - 2^{- x}

x = 0, x = - \frac{2 a - 1}{a}; a \neq = 0

Solution steps

a (x) = \frac{x}{( x + 2 )}

Simplify

\frac{x}{( x + 2 )} : \frac{x}{x + 2}

a (x) = \frac{x}{x + 2}

Multiply both sides by

x + 2

a x (x + 2) = x

Solve

a x (x + 2) = x : x = 0, x = - \frac{2 a - 1}{a}; a \neq = 0

x = 0, x = - \frac{2 a - 1}{a}; a \neq = 0

Verify Solutions

Find undefined (singularity) points:

x = - 2

Combine undefined points with solutions:

x = 0, x = - \frac{2 a - 1}{a}; a \neq = 0

\frac{( x - 1 )}{2 - x} = \frac{( x - 2 )}{3 - 1}

2 \frac{( x - 1 )}{( x - 3 )} - 3 \frac{( x + 3 )}{( x - 1 )} = 5 l

\frac{2}{4 y + 8} = 0

x^{- 2} - x^{- 1} - 6 = 0

\frac{( 2 x ^{2} + 9 x - 5 )}{( x ^{4} + 1 )} = 0

What is the answer to a(x)= x/((x+2)),b(x)-2^{-x} ?
The answer to a(x)= x/((x+2)),b(x)-2^{-x} is x=0,x=-(2a-1)/a ;\quad a\ne 0