What is the answer to (x^2-4)/(x^2)=3 ?

The answer to (x^2-4)/(x^2)=3 is x=sqrt(2)i,x=-sqrt(2)i

Solve for x: (x^2-4)/(x^2)=3

The solution is x=sqrt(2)i,x=-sqrt(2)i

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\frac{x ^{2} - 4}{x ^{2}} = 3

x = 2 i, x = - 2 i

Solution steps

\frac{x ^{2} - 4}{x ^{2}} = 3

Multiply both sides by

x^{2}

x^{2} - 4 = 3 x^{2}

Solve

x^{2} - 4 = 3 x^{2} : x = 2 i, x = - 2 i

x = 2 i, x = - 2 i

\frac{1}{( x ^{2} + 1 )} + \frac{1}{( x - 1 )} = \frac{6}{5}

x, \frac{3}{x} + \frac{2}{y} = 0

\frac{3 x}{7 x + 20} = \frac{24}{76}

- x - 2 - 7 x (\frac{1}{x} - \frac{1}{2}) = \frac{( 1 + \frac{x}{2} )}{2} + \frac{11}{2}

\frac{20}{5} = \frac{30}{x}

What is the answer to (x^2-4)/(x^2)=3 ?
The answer to (x^2-4)/(x^2)=3 is x=sqrt(2)i,x=-sqrt(2)i
Solve for x: (x^2-4)/(x^2)=3
The solution is x=sqrt(2)i,x=-sqrt(2)i