What is the answer to (7y+4}{y+2}=\frac{-4)/3 ?

The answer to (7y+4}{y+2}=\frac{-4)/3 is y=-4/5

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(7y+4}{y+2}=\frac{-4)/3

\frac{7 y + 4}{y + 2} = \frac{- 4}{3}

y = - \frac{4}{5}

Decimal Notation

y = - 0.8

Solution steps

\frac{7 y + 4}{y + 2} = \frac{- 4}{3}

Cross multiply

21 y + 12 = - 4 y - 8

Move

12

to the right side

21 y = - 4 y - 20

Move

4 y

to the left side

25 y = - 20

Divide both sides by

25

y = - \frac{4}{5}

Verify Solutions

Find undefined (singularity) points:

y = - 2

Combine undefined points with solutions:

y = - \frac{4}{5}

\frac{( 9 x + 7 )}{2 - ( x - \frac{( x - 2 )}{2} )} = 36

\frac{x ^{2} + 1}{( x ^{2} ) - 5 ( a + \frac{1}{x} ) + 2} = 0

\frac{\frac{22}{15}}{( \frac{1}{3} - 5 x )} = - \frac{22}{5}

\frac{7}{15 \cdot x + 3} = \frac{3}{5}

x, r + s - 2 t = (2 x + y)^{- 2}

What is the answer to (7y+4}{y+2}=\frac{-4)/3 ?
The answer to (7y+4}{y+2}=\frac{-4)/3 is y=-4/5
Solve for y: (7y+4}{y+2}=\frac{-4)/3
The solution is y=-4/5