What is the answer to ((n+1)!)/((n+3)!)= 1/20 ?

The answer to ((n+1)!)/((n+3)!)= 1/20 is n=2,n=-7

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((n+1)!)/((n+3)!)= 1/20

\frac{( n + 1 ) !}{( n + 3 ) !} = \frac{1}{20}

n = 2, n = - 7

Solution steps

\frac{( n + 1 ) !}{( n + 3 ) !} = \frac{1}{20}

Cross multiply

20 = (n + 3) (n + 2)

Solve

20 = (n + 3) (n + 2) : n = 2, n = - 7

n = 2, n = - 7

\frac{x + 1}{x} = 1

\frac{1}{f} + 40 + \frac{1}{25} + f = \frac{1}{f}

\frac{b + 1}{b} = - 3

t, g = 2 \frac{h}{t ^{2}}

\frac{3 - 1}{x} = \frac{1}{2}

What is the answer to ((n+1)!)/((n+3)!)= 1/20 ?
The answer to ((n+1)!)/((n+3)!)= 1/20 is n=2,n=-7
Solve for n: ((n+1)!)/((n+3)!)= 1/20
The solution is n=2,n=-7