What is the answer to x^2+1/(x^2)-3x-3/x+4=0 ?

The answer to x^2+1/(x^2)-3x-3/x+4=0 is x=1,x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2

Solve for x: x^2+1/(x^2)-3x-3/x+4=0

The solution is x=1,x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2

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x^{2} + \frac{1}{x ^{2}} - 3 x - \frac{3}{x} + 4 = 0

x = 1, x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

Solution steps

x^{2} + \frac{1}{x ^{2}} - 3 x - \frac{3}{x} + 4 = 0

Multiply by LCM

x^{4} + 1 - 3 x^{3} - 3 x + 4 x^{2} = 0

Solve

x^{4} + 1 - 3 x^{3} - 3 x + 4 x^{2} = 0 : x = 1, x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

x = 1, x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = 1, x = \frac{1}{2} + i \frac{3}{2}, x = \frac{1}{2} - i \frac{3}{2}

a = - 10 m \cdot s^{- 2}

\frac{x ^{2} + 3 x - 20}{( x ^{2} + 3 x )} = 8

\frac{a ^{3} x \cdot a ^{4} x}{( a ^{3} x ) 2} = 4 a

\frac{x ^{2} + 5}{x} = (- 3 - x)

\frac{6 a}{a ^{2} + 9} = 1

What is the answer to x^2+1/(x^2)-3x-3/x+4=0 ?
The answer to x^2+1/(x^2)-3x-3/x+4=0 is x=1,x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2
Solve for x: x^2+1/(x^2)-3x-3/x+4=0
The solution is x=1,x= 1/2+i(sqrt(3))/2 ,x= 1/2-i(sqrt(3))/2