What is the answer to (x^2+5)/x =(-3-x) ?

The answer to (x^2+5)/x =(-3-x) is x=-3/4+i(sqrt(31))/4 ,x=-3/4-i(sqrt(31))/4

Solve for x: (x^2+5)/x =(-3-x)

The solution is x=-3/4+i(sqrt(31))/4 ,x=-3/4-i(sqrt(31))/4

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\frac{x ^{2} + 5}{x} = (- 3 - x)

x = - \frac{3}{4} + i \frac{31}{4}, x = - \frac{3}{4} - i \frac{31}{4}

Solution steps

\frac{x ^{2} + 5}{x} = (- 3 - x)

Multiply both sides by

x

x^{2} + 5 = (- 3 - x) x

Solve

x^{2} + 5 = (- 3 - x) x : x = - \frac{3}{4} + i \frac{31}{4}, x = - \frac{3}{4} - i \frac{31}{4}

x = - \frac{3}{4} + i \frac{31}{4}, x = - \frac{3}{4} - i \frac{31}{4}

\frac{6 a}{a ^{2} + 9} = 1

\frac{\frac{98}{9}}{y} = \frac{38}{27}

2 (\frac{x ^{2} + 1}{( x ^{2} )}) - 3 (\frac{x + 1}{x}) = 1

\frac{( 0.3 + 0.7 y )}{y} = 0.85

\frac{1}{3} + \frac{a}{x} = - 1

What is the answer to (x^2+5)/x =(-3-x) ?
The answer to (x^2+5)/x =(-3-x) is x=-3/4+i(sqrt(31))/4 ,x=-3/4-i(sqrt(31))/4
Solve for x: (x^2+5)/x =(-3-x)
The solution is x=-3/4+i(sqrt(31))/4 ,x=-3/4-i(sqrt(31))/4