What is the answer to 2x^2+sqrt(5x)-5=0 ?

The answer to 2x^2+sqrt(5x)-5=0 is x\approx 1.14237…

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2x^2+sqrt(5x)-5=0

2 x^{2} + 5 x - 5 = 0

x \approx 1.14237 \dots

Solution steps

2 x^{2} + 5 x - 5 = 0

Remove square roots

5 x = 4 x^{4} - 20 x^{2} + 25

Solve

5 x = 4 x^{4} - 20 x^{2} + 25 : x \approx 2.02236 \dots, x \approx 1.14237 \dots

x \approx 2.02236 \dots, x \approx 1.14237 \dots

Verify Solutions:

x \approx 2.02236 \dots

False

, x \approx 1.14237 \dots

True

The solution is

x \approx 1.14237 \dots

4 \frac{x}{( x + 1 )} + 3 \frac{( x + 1 )}{x} = 8

\frac{x}{8} = \frac{x}{18}

64 (x) (64) = 32 \cdot 32

x^{2} + x + 1 = 1

m = \frac{m ^{0}}{1 - \frac{v ^{2}}{c ^{2}}}

What is the answer to 2x^2+sqrt(5x)-5=0 ?
The answer to 2x^2+sqrt(5x)-5=0 is x\approx 1.14237…
Solve for x: 2x^2+sqrt(5x)-5=0
The solution is x\approx 1.14237…