What is the answer to 1+sqrt(x+1-2\sqrt{8-x)}=sqrt(x) ?

The answer to 1+sqrt(x+1-2\sqrt{8-x)}=sqrt(x) is x=4

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1+sqrt(x+1-2\sqrt{8-x)}=sqrt(x)

1 + x + 1 - 2 8 - x = x

x = 4

Solution steps

1 + x + 1 - 2 8 - x = x

Remove square roots

32 - 4 x = 4 x

Solve

32 - 4 x = 4 x : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

x + 2 = 5

x = - 2.3

\frac{x ^{2}}{3 + x ^{\frac{1}{3}} - 2} = 0

7^{1} + x + x^{\frac{1}{3}} - 2 = 0

x - 2 = 1

What is the answer to 1+sqrt(x+1-2\sqrt{8-x)}=sqrt(x) ?
The answer to 1+sqrt(x+1-2\sqrt{8-x)}=sqrt(x) is x=4
Solve for x: 1+sqrt(x+1-2\sqrt{8-x)}=sqrt(x)
The solution is x=4