What is the answer to 7^1+x+x^{1/3}-2=0 ?

The answer to 7^1+x+x^{1/3}-2=0 is x\approx-3.48401…

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7^1+x+x^{1/3}-2=0

7^{1} + x + x^{\frac{1}{3}} - 2 = 0

x \approx - 3.48401 \dots

Solution steps

7^{1} + x + x^{\frac{1}{3}} - 2 = 0

Expand

7^{1} + x + x^{\frac{1}{3}} - 2 : x + x^{\frac{1}{3}} + 5

x + x^{\frac{1}{3}} + 5 = 0

Remove roots

x = - x^{3} - 15 x^{2} - 75 x - 125

Solve

x = - x^{3} - 15 x^{2} - 75 x - 125 : x \approx - 3.48401 \dots

x \approx - 3.48401 \dots

Verify Solutions:

x \approx - 3.48401 \dots

True

The solution is

x \approx - 3.48401 \dots

x - 2 = 1

x^{2} - x = 3 x - 5

(x^{2} - 1) \cdot 2 x - 1 = 0

x, t^{- 1} = \frac{( l \cdot t ^{- 1} )}{x}

\frac{1}{3} \cdot 5 x - \frac{1}{2} = \frac{3}{2} \cdot 5 x - 2 5 x

What is the answer to 7^1+x+x^{1/3}-2=0 ?
The answer to 7^1+x+x^{1/3}-2=0 is x\approx-3.48401…
Solve for x: 7^1+x+x^{1/3}-2=0
The solution is x\approx-3.48401…