What is the answer to sqrt(x^2-x)=sqrt(3x-5) ?

The answer to sqrt(x^2-x)=sqrt(3x-5) is No Solution for x\in\mathbb{R}

Solve for x: sqrt(x^2-x)=sqrt(3x-5)

The solution is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - x = 3 x - 5

No Solution for x \in R

Solution steps

x^{2} - x = 3 x - 5

Square both sides:

x^{2} - x = 3 x - 5

x^{2} - x = 3 x - 5

Solve

x^{2} - x = 3 x - 5 :

No Solution for

x \in R

No Solution for x \in R

(x^{2} - 1) \cdot 2 x - 1 = 0

x, t^{- 1} = \frac{( l \cdot t ^{- 1} )}{x}

\frac{1}{3} \cdot 5 x - \frac{1}{2} = \frac{3}{2} \cdot 5 x - 2 5 x

x + 3 = x + 1

x^{2} + 13 = 8 - x

What is the answer to sqrt(x^2-x)=sqrt(3x-5) ?
The answer to sqrt(x^2-x)=sqrt(3x-5) is No Solution for x\in\mathbb{R}
Solve for x: sqrt(x^2-x)=sqrt(3x-5)
The solution is No Solution for x\in\mathbb{R}