What is the answer to (-(sqrt(2x+1)))/(3+2)=0 ?

The answer to (-(sqrt(2x+1)))/(3+2)=0 is x=-1/2

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(-(sqrt(2x+1)))/(3+2)=0

\frac{- ( 2 x + 1 )}{3 + 2} = 0

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

\frac{- ( 2 x + 1 )}{3 + 2} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 2 x + 1 = 0

Square both sides:

2 x + 1 = 0

2 x + 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

x = - \frac{1}{2}

Verify Solutions:

x = - \frac{1}{2}

True

The solution is

x = - \frac{1}{2}

x = 0.25

x, z = x (x^{2} + y^{2})^{\frac{1}{2}}

5 x - 6 = - 1

a - 1 = 7 - a

(x - 4)^{2} + (1 - x)^{2} = 7

What is the answer to (-(sqrt(2x+1)))/(3+2)=0 ?
The answer to (-(sqrt(2x+1)))/(3+2)=0 is x=-1/2
Solve for x: (-(sqrt(2x+1)))/(3+2)=0
The solution is x=-1/2