What is the answer to sqrt(x+1)+sqrt(x-1)=2 ?

The answer to sqrt(x+1)+sqrt(x-1)=2 is x= 5/4

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sqrt(x+1)+sqrt(x-1)=2

x + 1 + x - 1 = 2

x = \frac{5}{4}

Decimal Notation

x = 1.25

Solution steps

x + 1 + x - 1 = 2

Remove square roots

4 = 16 x - 16

Solve

4 = 16 x - 16 : x = \frac{5}{4}

x = \frac{5}{4}

Verify Solutions:

x = \frac{5}{4}

True

The solution is

x = \frac{5}{4}

x + 1 + x - 1 = 1

12 - x + 3 = 15

\frac{x ^{\frac{1}{3}} + 2 x ^{2}}{3 - x} = 0

x = x + 6

\frac{( x )}{( 1 - x )} + \frac{( 1 + x )}{( x )} = \frac{5}{2}

What is the answer to sqrt(x+1)+sqrt(x-1)=2 ?
The answer to sqrt(x+1)+sqrt(x-1)=2 is x= 5/4
Solve for x: sqrt(x+1)+sqrt(x-1)=2
The solution is x= 5/4