What are the solutions to the equation (x-4)^2=15 ?

The solutions to the equation (x-4)^2=15 are x=sqrt(15)+4,x=-sqrt(15)+4

Find the zeros of (x-4)^2=15

The zeros of (x-4)^2=15 are x=sqrt(15)+4,x=-sqrt(15)+4

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(x - 4)^{2} = 15

x = 15 + 4, x = - 15 + 4

Decimal Notation

x = 7.87298 \dots, x = 0.12701 \dots

Solution steps

(x - 4)^{2} = 15

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 15 : x = 15 + 4

Solve

x - 4 = - 15 : x = - 15 + 4

The solutions to the quadratic equation are:

x = 15 + 4, x = - 15 + 4

\frac{- 5 c ^{- 2}}{- 4 ( c ^{4} ) ^{4}}

e^{5 l n (3)}

0 = x^{2} - 9 x - 36

- 5 x = - 7

x - 23 \leq 3

What are the solutions to the equation (x-4)^2=15 ?
The solutions to the equation (x-4)^2=15 are x=sqrt(15)+4,x=-sqrt(15)+4
Find the zeros of (x-4)^2=15
The zeros of (x-4)^2=15 are x=sqrt(15)+4,x=-sqrt(15)+4