What are the solutions to the equation 0=x^2-9x-36 ?

The solutions to the equation 0=x^2-9x-36 are x=12,x=-3

Find the zeros of 0=x^2-9x-36

The zeros of 0=x^2-9x-36 are x=12,x=-3

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0 = x^{2} - 9 x - 36

x = 12, x = - 3

Solution steps

0 = x^{2} - 9 x - 36

Switch sides

x^{2} - 9 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 36) = 15

x_{1, 2} = \frac{- ( - 9 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 15}{2 \cdot 1}

x = \frac{- ( - 9 ) + 15}{2 \cdot 1} : 12

x = \frac{- ( - 9 ) - 15}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 12, x = - 3

- 5 x = - 7

x - 23 \leq 3

- \frac{2}{3} \cdot 5

(\frac{2 x ^{2}}{3 x ^{3} y ^{2}})^{3}

51 2^{- \frac{1}{3}}

What are the solutions to the equation 0=x^2-9x-36 ?
The solutions to the equation 0=x^2-9x-36 are x=12,x=-3
Find the zeros of 0=x^2-9x-36
The zeros of 0=x^2-9x-36 are x=12,x=-3